Every distinction begins with one topic at a time.- start now
| Item | Paper 1, Physics |
|---|---|
| Total marks | 150 |
| Duration | 3 hours, so 180 minutes |
| Sections | none; QUESTION 1 is the multiple-choice question, then QUESTIONS 2 to 10 are structured |
| QUESTION 1 | ten subquestions, 1.1 to 1.10, at 2 marks each = 20 marks |
| QUESTIONS 2 to 10 | 130 marks of structured questions |
| Content groups | Mechanics 65, Electricity and magnetism 55, Waves sound and light 15, Matter and materials 15 |
| Topics examined | Newton's laws and vectors, momentum and impulse, vertical projectile motion, work energy and power, the Doppler effect, electrostatics, electric circuits, electrodynamics, the photoelectric effect with atomic spectra |
| Data sheet supplied | the physics sheet only: Table 1 constants and Table 2's five formula blocks |
| Marked | externally, per step, with positive marking between subquestions |
Paper 1 is Physics: 150 marks, 3 hours, no lettered sections. QUESTION 1 is ten multiple-choice subquestions at 2 marks each = 20 marks, then QUESTIONS 2 to 10 carry the other 130. Content is never restricted by the term it was taught in, so a Term 1 topic is exactly as examinable as a Term 3 topic, in the Preliminary paper and in the Final. Paper 2 examines the Chemistry half of the subject in a separate 150-mark sitting with its own data sheet, and is covered by the companion Chemistry pack, so the two papers together make up the 300-mark subject total.
| Cognitive level | Share of Paper 1 | Marks, roughly | Typical instruction |
|---|---|---|---|
| Remember | 15% | about 23 | define, state, name, write down the formula |
| Understand | 35% | about 53 | explain, describe, interpret a graph, compare two situations |
| Apply / Analyse | 40% | about 60 | calculate in a new context, analyse a circuit or a v-t graph, deduce |
| Evaluate / Create | 10% | about 15 | judge whether a conclusion is valid, improve an investigation, design a method |
The four content-GROUP totals are the national planning weights the examiners build the paper to, so they hold year after year. The split within a group is reconstructed from two recent sittings, which means an individual paper can move a mark or two either way, never enough to change the revision order. The table sums to exactly 150.
| Paper 1 topic | Marks | Weight | Priority |
|---|---|---|---|
| Electric Circuits (with internal resistance) | 23 | 15% | Highest single question on the paper |
| Vectors, Forces and Newton's Laws | 18 | 12% | High |
| Vertical Projectile Motion (1D) | 17 | 11% | High |
| Electrostatics | 17 | 11% | High |
| Work, Energy and Power | 16 | 11% | High |
| Doppler Effect | 15 | 10% | Medium |
| Electrodynamics | 15 | 10% | Medium |
| Photoelectric Effect & Atomic Spectra | 15 | 10% | Medium |
| Momentum and Impulse | 14 | 9% | Medium |
| Total | 150 | 100% | QUESTION 1's 20 MCQ marks come OUT of these rows |
Grouped officially: Mechanics 18 + 14 + 17 + 16 = 65, Electricity and magnetism 17 + 23 + 15 = 55, Waves sound and light 15, Matter and materials 15. Percentages are rounded to whole numbers, so the column reads 99. QUESTION 1 never gets its own row, because its 20 marks are sampled out of the topic rows above rather than added to them: add them twice and a 150-mark paper looks like a 170-mark one, and every topic percentage comes out too small.
| Question | Usual topic | Group |
|---|---|---|
| Q1 (1.1 to 1.10) | multiple choice, 2 marks each, sampling every topic on the paper | all four |
| Q2 | vectors, forces and Newton's laws | Mechanics |
| Q3 | vertical projectile motion in one dimension | Mechanics |
| Q4 | momentum and impulse | Mechanics |
| Q5 | work, energy and power | Mechanics |
| Q6 | the Doppler effect, sound and red shift | Waves, sound and light |
| Q7 | electrostatics, Coulomb's law and electric fields | Electricity and magnetism |
| Q8 | electric circuits, almost always with internal resistance | Electricity and magnetism |
| Q9 | electrodynamics, machines and alternating current | Electricity and magnetism |
| Q10 | the photoelectric effect and atomic spectra | Matter and materials |
The ORDER above is stable: two recent sittings ran exactly this spine. What moves year to year is the marks per question and how many questions a topic is split across, so plan around the topic order and never promise yourself a fixed mark per question number.
Practical work is assessed inside the school, but the SKILLS of an investigation are examinable in Paper 1 itself, and the Physics contexts they are set in come straight from the prescribed work. The Term 3 Physics experiment has two parts: determining the internal resistance of a battery, then building a series-parallel network from known resistors, measuring its equivalent resistance with an ammeter and a voltmeter, and comparing that with the theoretical value. Those are exactly the two contexts the circuits question keeps returning to.
| Skill the paper asks for | What earns the mark |
|---|---|
| Formulate the investigative question | name the independent and the dependent variable in one sentence, phrased as a question |
| Write a hypothesis | a testable statement predicting a direction of change, never a question and never "I think" |
| Identify the variables | independent (what you change), dependent (what you measure), controlled (what you deliberately keep constant) |
| List apparatus | the specific instrument, not "equipment": ammeter, voltmeter, rheostat, connecting wires, cell |
| Justify repeating the reading | repeated trials reduce the effect of random error, so an average is more reliable |
| State a precaution | open the switch between readings so the cell does not warm and its internal resistance drift |
| Draw and read the graph | V against I for the internal-resistance experiment: the gradient's magnitude is r and the V-intercept is the emf |
| Evaluate a conclusion | say whether the DATA supports it, and name the specific measurement that does or does not |
A calculation is marked step by step, not as one block, so knowing where the individual marks sit changes how you write. Every rule below applies to this paper.
| Rule | Consequence |
|---|---|
| Marks are given for the correct formula, the correct substitution, and the answer with its unit | three separate places to earn marks in one calculation |
| An inappropriate formula scores zero, however perfect the substitutions | choosing the right equation is the first real mark |
| A substitution error inside a correct formula | formula and substitution marks kept, the remaining marks lost |
| No formula written but the substitutions all correct | one mark forfeited |
| Substitutions must appear INSIDE the formula | a list of values above the formula risks the substitution mark |
| Changing the subject of a formula carries no mark in itself | write the formula in its data-sheet form first, then rearrange |
| A formula written with no calculation attempted | no formula mark either |
| Round the final answer to at least two decimal places unless told otherwise | one decimal place is at risk |
| Units belong on the final answer | a correct number without its unit loses the answer mark |
| Two answers given and neither struck out | only the FIRST is marked, even if the second is the right one |
| Positive marking between subquestions | a wrong value carried forward correctly still earns the later marks, but it does not rescue a slip made inside a single multistep subquestion |
Q: A 4 kg block is pulled along a rough horizontal surface by a 30 N force parallel to the surface. The frictional force is 10 N. Calculate the acceleration. (5)
Fnet = ma formula, mark 1
Taking the direction of motion as positive: Fnet = 30 + (−10) = 20 N correct net force, mark 2
20 = (4)a substitution inside the formula, mark 3
a = 5,00 m·s−2 value, mark 4
in the direction of the applied force direction on a vector answer, mark 5
∴ only two of the five marks depend on the arithmetic. Writing Fnet = ma and the net-force line banks two marks before a single calculator key is pressed, which is exactly why a blank answer is the most expensive thing you can write.
RTQ, Read The Question: underline the command word and every given value before writing a line of working. Show your workings: formula first, then the substitution inside it, then the final line, because each step is marked separately. Units and direction: a unit on every measured quantity and a stated direction on every vector answer. Check: reserve the last few minutes for units, directions, rounding, and confirming every subquestion has an answer written down.
A syllabus feels enormous only until you know exactly which fraction of it the marks actually live in.- on reading the mark weighting before the content
Paper 1 is the Physics paper: 150 marks over 3 hours with no lettered sections. QUESTION 1 is ten multiple-choice subquestions worth 20 marks, then QUESTIONS 2 to 10 carry the other 130. Officially the marks group as Mechanics 65, Electricity and magnetism 55, Waves sound and light 15 and Matter and materials 15, exactly 150, and the biggest single question is electric circuits at 23 marks with Newton's laws next at 18. This paper's cognitive spread is 15% remember, 35% understand, 40% apply and analyse and 10% evaluate and create, which is why practising unfamiliar scenarios beats re-reading formulas. Calculations are marked per step, so write the formula, substitute inside it, round the final answer to at least two decimal places, attach the unit and give vectors a direction, and strike out any attempt you do not want marked, because only the first answer is read.
| Quantity | Formula | Typical mark cost |
|---|---|---|
| Parallel component (drives motion down the slope) | Fg∥ = mg sinθ | 2 marks: formula line + substitution |
| Perpendicular component (presses into the surface) | Fg⊥ = mg cosθ | 2 marks |
| Normal force | from vertical equilibrium - NOT automatically mg | 1 mark, only if correctly justified |
| Law | Core idea | Formula form |
|---|---|---|
| 1st (inertia) | no change in motion without a resultant force | ΣF = 0 → a = 0 |
| 2nd | a is proportional to F, inversely proportional to m | Fnet = ma |
| 3rd | every force has an equal, opposite reaction on the OTHER object | FA on B = −FB on A |
Fnet = maFg = mgfs(max) = μsN and fk = μkNF = Gm1m2⁄d2g = GM⁄d2, with G = 6,67×10−11 N·m2·kg−2 (given on the data sheet, never derived)
Q: A 38 kg crate rests on a ramp inclined at 22° to the horizontal. The coefficient of static friction is 0,40; the coefficient of kinetic friction is 0,32. (a) Show whether the crate slides down under gravity alone. (b) Calculate its acceleration once sliding.
Fg∥ = mg sinθ = (38)(9,8)(sin22°) = 372,4 × 0,37461 ≈ 139,50 N
FN = Fg⊥ = mg cosθ = 372,4 × 0,92718 ≈ 345,28 N
Maximum static friction = μsN = (0,40)(345,28) ≈ 138,11 N
Since 139,50 N > 138,11 N, the driving component just exceeds the maximum available static friction, so the crate slides.
Once sliding: fk = μkN = (0,32)(345,28) ≈ 110,49 N (up the slope)
Fnet = Fg∥ − fk = 139,50 − 110,49 ≈ 29,01 N down the slope
Fnet = ma → a = 29,01 ÷ 38 ≈ 0,76 m·s−2 down the slope
∴ The crate slides, accelerating at about 0,76 m·s−2 down the incline
Q: Block A (10 kg) sits on a rough horizontal table (μk = 0,22) and is connected by a light inextensible string, over a frictionless pulley, to a hanging Block B (6 kg). Calculate the system's acceleration and the string tension.
Block B (vertical): mBg − T = mBa → 58,8 − T = 6a
Block A (horizontal): T − fk = mAa, where fk = μkmAg = (0,22)(10)(9,8) = 21,56 N
So T − 21,56 = 10a
Adding the two equations to eliminate T: 58,8 − 21,56 = 16a → 37,24 = 16a → a ≈ 2,33 m·s−2
Substituting back: T = 10(2,33) + 21,56 ≈ 44,8 N
∴ The system accelerates at about 2,33 m·s−2, with a string tension of about 44,8 N
Q: Calculate the gravitational force of attraction between the Earth (mass 5,97×1024 kg) and a 1 500 kg satellite orbiting at 6,8×106 m from the Earth's centre.
F = Gm1m2⁄d2 = (6,67×10−11)(5,97×1024)(1 500) ÷ (6,8×106)2
= (5,97×1017) ÷ (4,62×1013)
∴ F ≈ 1,29×104 N
Q: Two cables pull on a boulder. Cable 1 exerts 50 N at 35° above the horizontal, up and to the right. Cable 2 exerts 38 N at 60° above the horizontal on the other side, up and to the left. Calculate the magnitude and direction of the resultant force.
Taking right as positive x and up as positive y:
F1x = 50cos35° ≈ 40,96 N, F1y = 50sin35° ≈ 28,68 N
F2x = −38cos60° = −19,00 N, F2y = 38sin60° ≈ 32,91 N
ΣFx = 40,96 − 19,00 = 21,96 N ΣFy = 28,68 + 32,91 = 61,59 N
R = √(21,962 + 61,592) ≈ 65,4 N
θ = tan−1(61,59 ÷ 21,96) ≈ 70,4° above the horizontal, toward the side where ΣFx is positive
∴ The resultant is about 65,4 N at 70,4° above the horizontal
Memory aid: "FBD before formulas" - sketch and label every force on the object before writing a single equation. On a slope, remember the component ALONG the surface always pairs with sinθ, and the component INTO the surface always pairs with cosθ, provided θ is measured from the incline itself - sketch the little right-angle triangle every time instead of guessing which ratio to use.
A force that never appears in your diagram can still cost you the mark - draw first, calculate second.- on free-body diagrams
Draw the free-body diagram first, every time - it is where the marks start. Resolve weight into Fg∥ and Fg⊥ on a slope, test static friction against its maximum before assuming motion, then apply Fnet = ma per object. A Newton's third law pair never appears twice in the same diagram. FN equals mg only on a flat surface with no other vertical force. Gravitation follows F = Gm1m2⁄d2, the same inverse-square shape you will meet again this year.
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